Typescript Array.filter(Boolean)
Out of the box, Typescript doesn’t play well with Array.filter(Boolean)
. There’s a lot of history to this issue and it hasn’t fully been fixed yet. In the below snippet, the returned type from the filter should be string[]
, but instead it’s (string | null | undefined)[]
.
const foo: (string | null | undefined)[] = [];
const bar: string[] = foo.filter(Boolean);
// ^^^
// Type '(string | null | undefined)[]' is not assignable to type 'string[]'.
To fix the issue, you can add an overload to Array.prototype.filter()
for the special case of using the boolean constructor as the predicate. Save the below snippet as lib.es5.d.ts
:
/**
* Fixes https://github.com/microsoft/TypeScript/issues/16655 for `Array.prototype.filter()`
* For example, using the fix the type of `bar` is `string[]` in the below snippet as it should be.
*
* const foo: (string | null | undefined)[] = [];
* const bar = foo.filter(Boolean);
*
* For related definitions, see https://github.com/microsoft/TypeScript/blob/master/src/lib/es5.d.ts
*
* Original licenses apply, see
* - https://github.com/microsoft/TypeScript/blob/master/LICENSE.txt
* - https://stackoverflow.com/help/licensing
*/
/** See https://stackoverflow.com/a/51390763/1470607 */
type Falsy = false | 0 | "" | null | undefined;
interface Array<T> {
/**
* Returns the elements of an array that meet the condition specified in a callback function.
* @param predicate A function that accepts up to three arguments. The filter method calls the predicate function one time for each element in the array.
* @param thisArg An object to which the this keyword can refer in the predicate function. If thisArg is omitted, undefined is used as the this value.
*/
filter<S extends T>(predicate: BooleanConstructor, thisArg?: any): Exclude<S, Falsy>[];
}
And then add it to your tsconfig
as an include:
{
"include": [
"lib.es5.d.ts"
]
}